hey plato buddie, the answer is A! zero
The order of the reaction for the given rate law is zero.
Order of the reaction is defined as the sum of the exponents or powers to which the molar concentration in the rate law equation are raised to express the observed rate of the reaction. For a given general equation:
Rate law is given as:
Order of the reaction will be = a
For the given rate law:
In the rate law, anything raised to power 0 is 1.
Order of the give rate law = 0
And, hence, the order of the reaction will be zero.
We call this type of problem, "determining a rate law by the method of initial rates."
We want to know how much a change in the concentration of a reactant will change the rate of a reaction.
We must measure the reaction rate once. Then we repeat the experiment. We change the concentration of one reactant and leave everything else the same.
The equation for this reaction is
2ClO₂ + 2OH⁻ ⟶ ClO₃⁻ + ClO₂⁻ + H₂O
The general form of the rate law is
Our task is to find the values of m and n.
1. Calculate m
Consider experiments 1 and 2 .
In going from Experiment 2 to Experiment 1, we tripled the concentration and the rate tripled.
If tripling the concentration triples the rate, the reaction is 1st order.
m = 1, so the rate law becomes
2. Calculate n
Consider experiments 2 and 3 .
In going from Experiment 3 to Experiment 3, we tripled the concentration and the rate tripled.
n = 1, so the rate law becomes
3. Write the overall order
Overall order = m + n = 1 + 1 = 2
The overall reaction order is 2.
4. Calculate k
From Experiment 1,