- 16t² +400 = 0
t² = 400/16
t² = 25
t = 5 or t = - 5
through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i. when x = 0, y = 3, so the y-intercept is (0, 3).
if graphs are part of the problem statement, share them. .
the expected value of the random variable : 0, 1 and 2