A. 130.7 N/m
By Hook's law
Force(F) = Spring constant(k) × Extention (d)
F = k× d ⇒ k = F/d
To find Force(F) you know it is the weight of the object. Considering g = 9.8 ms⁻²
k = 2×9.8/0.15 = 130.7 Nm⁻¹
for small deformations of an object, the displacement is directly proportional to the deforming force or load.
Under these conditions the object returns to its original shape and size upon removal of the load.
The deforming force may be applied to a solid by stretching, compressing,etc. so a spring shows an elastic behavior according to Hooke’s law
applied force( F) = constant (k)* displacement in length (x)
F = kx.
The value of k dependson the kind of elastic material on its dimensions and shape.
C and E are a linear pair, meaning the total angle measure is 180
c=147 subtract that from 180
what is the question here