The given function is
According to the first principle of the derivative,
Cancel out common factors.
By applying limit, we get
Put x=2, to find the y-coordinate of point of tangency.
The coordinates of point of tangency are (2,0.25).
The slope of tangent at x=2 is
Substitute x=2 in equation 2.
The slope of the tangent line at x=2 is -0.25.
The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).
Using point slope form the equation of tangent is
Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.